alpha decay equation calculator

Thus this second reaction seems to be more energetic, hence more favorable than the alpha-decay, yet it does not occur (some decays involving C-12 have been observed, but their branching ratios are much smaller). An example of beta decay is . Nuclear reactions need to have the sum of protons and neutrons the same on both sides of the equation. 2. So we think about what's so we put a one right here. The general rule for decay is best written in the format Z A X N. If a certain nuclide is known to decay (generally this information must be looked up in a table of isotopes, such as in Appendix B ), its decay equation is (31.4.3) X Z A N Y N 2 Z 2 A 4 + He 2 2 4 ( d e c a y) Other types of decay are less likely, because the Coulomb energy would increase considerably, thus the barrier becomes too high to be overcome. This is also equal to the total kinetic energy of the fragments, here Q = T X + T (here assuming that the parent nuclide is at rest). Write the nuclear equation for the decay of Po-210 if it undergoes 2 consecutive However \(\alpha\) decay is usually favored. Useful for calculating today's activity for any radioactive isotope. An atom of 241Am95 undergoes alpha decay and produces an alpha particle.Write a chemical equation showing this reaction. If the reaction involves electrons nucleus shed out neutrons one by one. Determine mathematic equation. The LibreTexts libraries arePowered by NICE CXone Expertand are supported by the Department of Education Open Textbook Pilot Project, the UC Davis Office of the Provost, the UC Davis Library, the California State University Affordable Learning Solutions Program, and Merlot. That's 144 neutrons. The energy Q derived from this decay is divided equally into the transformed nucleus and the Helium nucleus. You have reached the end of Physics lesson 20.3.2 Alpha Decay. View chapter Purchase book neutrons = 263 - 106 = 157, 106 - 2 = 104 protons Math is a subject that can be difficult for many students. Therefore, the resulting Thorium nucleus should have 234 mass numbers and 90 atomic numbers. Writing nuclear equations for alpha, beta, and gamma decay Google Classroom About Transcript Alpha, beta, and gamma decay are all ways that an unstable atom can decay into a more stable form. neutron turning into a proton, and this is an oversimplified Brief explanation of the three forms of radioactive emission: alpha, beta and gamma. Any help would be appreciated, thanks! The radioactive disintegration of alpha decay is a phenomenon in which the atomic nuclei which are unstable dissipate excess energy by ejecting the alpha particles in a spontaneous manner. This small change in the Z/N ratio is enough to put the nucleus into a more stable state (into the region of stable nuclei in the Chart of the Nuclides.). From (2.5) and (2.10) it is calculated that (4.17) From knowledge of the values of e, mHe, B, and r, E can be calculated. is the decay constant If an archaeologist found a fossil sample that contained 25% carbon-14 in comparison to a living sample, the time of the fossil sample's death could be determined by rearranging equation 1, since Nt, N0, and t1/2 are known. All elements heavier than lead can undergo alpha decay. You may enter date or time or a combination of both. The alpha particle is the same as a helium nucleus with 2 protons and 2 neutrons. An alpha particle is a very stable structure (we have explained that hydrogen and helium are very stable materials; indeed the Sun is mainly composed by hydrogen and helium elements). The exponent is thus a large number, giving a very low tunneling probabily: \(e^{-2 G}=e^{-89}=4 \times 10^{-39}\). First step In every alpha decay an alpha particle is formed though all alpha decay have different daughter nucleus . However, with practice and perseverance, it is possible to improve one's skills in this area. Alpha decay will cause transmutation to occur - this means that one element will turn into another element as the alpha particles are released. We will describe this pair of particles in their center of mass coordinate frames: thus we are interested in the relative motion (and kinetic energy) of the two particles. Gamow's Theory of Geiger-Nutall law defines the relationship between the energy of an alpha particle emitted with the decay constant for a radioactive isotope. Helmenstine, Todd. If a beta particle is If you would like to learn more about the other chemical calculator that gives instant results, stay tuned to Onlinecalculator.guru. If in case the alpha particles are swallowed, inhaled, or absorbed into the bloodstream which can have long-lasting damage on biological samples. I have a zero here, so Alpha decay (two protons. It can't take the place of an electron in a regular chemical reaction. Geiger-Nuttall law is used in nuclear physics and it relates the energy of the alpha particle emitted to the decay constant of a radioactive isotope. The radiocative decay formula is A = A0 e-0.693t/T. Alpha, beta, and gamma decay are all ways that an unstable atom can decay into a more stable form. Note that, here the term isotope refers to the combination of elements that are obtained with different number of neutrons. An alpha particle is the same as a helium-4 nucleus . Usually it is gamma decay but some radioactive synthesizers can tell you what radiation is has in its isotope. The formuls is E = (m. Beta Decay: A beta particle is also called an electron. One also learns how to find roots of all quadratic polynomials, using square roots (arising from the discriminant) when necessary. And also actually, 212 Po -10.3649 MeV. How does alpha decay help stabilize a nucleus? In some cases, linear algebra methods such as Gaussian elimination are used, with optimizations to increase . It's no longer in the excited state. Please enable JavaScript. Notice that its no coincidence that its called \(Q\). An example of an alpha decay equation is: A ZX Z . Nuclear equations are typically written in the format shown below. A \\ With this rule, it becomes abundantly clear that shorter-lived isotopes emit greater energy when compared to isotopes with longer lives. This of course represents the electron, so this is the electron that's The element which has 259 as the atomic weight is rutherfordium. Nuclear Chemistry Beta Decay: Write the beta decay equations for the following nuclides. Enjoy the "Alpha Decay" physics lesson? nucleus, uranium-238. Let's start with technetium-99m, and the m right here This means that there is a corresponding minimum (or energy optimum) around these numbers. The 0-day activity is to enter radioactivity on the base date. These calculators may help you determine current radioisotope inventories based on activity. Question: If the initial activity is 100, half-life is 15 seconds, and decay time is 10. This last probability can be calculated from the tunneling probability PT we studied in the previous section, given by the amplitude square of the wavefunction outside the barrier, \(P_{T}=\left|\psi\left(R_{\text {out}}\right)\right|^{2}\). Please provide any three of the following to calculate the fourth value. in its excited state, so a nucleus in its excited state, so it has more energy. For equation solving, Wolfram|Alpha calls the Wolfram Language's Solve and Reduce functions, which contain a broad range of methods for all kinds of algebra, from basic linear and quadratic equations to multivariate nonlinear systems. This decay occurs by following the radioactive laws, just as alpha decay does. This example problem demonstrates how to write a nuclear reaction process involving alpha decay. This equation is valid at any position inside the barrier: \[\kappa(r)=\sqrt{\frac{2 \mu}{\hbar^{2}}\left[V_{C o u l}(r)-Q_{\alpha}\right]}=\sqrt{\frac{2 \mu}{\hbar^{2}}\left(\frac{Z_{\alpha} Z^{\prime} e^{2}}{r}-Q_{\alpha}\right)} \nonumber\]. write our proton here. Now you can even download our Vedantu app for easier access to online study material and interactive classes. There are more advanced formulas for expressing roots of cubic and quartic polynomials, and also a number of numeric methods for approximating roots of arbitrary polynomials. Then you must check out this page. So this is just a visual representation of what's going on here, Alpha decay is the process of transformation of a radioactive nucleus by emitting helium. We can do the same calculation for the hypothetical decay into a 12C and remaining fragment (\({}_{81}^{188} \mathrm{TI}_{ \ 107}\)): \[Q_{12} C=c^{2}\left[m\left(\begin{array}{c} Although such methods are useful for direct solutions, it is also important for the system to understand how a human would solve the same problem. Alpha particles are He atoms which have had their electrons removed giving them a +2 charge. The largest exponent of appearing in is called the degree of . The atomic number of such nuclei has a mass that is four units less than the parent and an atomic number that is two units less than the parent. Direct link to Gray Can's post He didn't mention positro, Posted 6 years ago. Usually, in terms of high energy decay, this is due to a rearrangement of nucleons in a nucleus into a lower energy state (this is what is referred to as gamma decay), nuclear fission, or various other means. have zero charge on the left, plus one on the right, we But inside the nucleus, the nucleons are bound to one another by the strong nuclear force, so you also get quantized energy levels for that smaller system. The decay rate is then given by \(\lambda_{\alpha}=f P_{T}\). As a result, Wolfram|Alpha also has separate algorithms to show algebraic operations step by step using classic techniques that are easy for humans to recognize and follow. Why theres no spontaneous fission into equal daughters? APXS is a process that is used to determine the elemental composition of rocks and soil. In Physics and Chemistry, Q-value is defined as the difference between the sum of the rest masses of original reactants and the sum of final product masses. Is neutron made up of proton and electron and antineutrino? So a neutron turning into a proton. a beta particle in here, so zero and negative one, #""_106^263Sg# --> #""_104^259Rf# + #""_2^4He#. Scintillation counters can use different materials specialized for specific types of radiation as well. The mass of the alpha particles is relatively large and has a positive charge. The most common forms of Radioactive decay are: The articles on these concepts are given below in the table for your reference: Stay tuned to BYJUS and Fall in Love with Learning! Consider for example the reaction \({ }^{238} \mathrm{U} \rightarrow{ }^{234} \mathrm{Th}+\alpha\). We already talked about An example of alpha decay is when uranium-238 gives off an alpha particle and produces thorium-234.Feb 5, 2022 This is basically due to the contact of emitted particles with membranes and living cells. Direct link to Mahdi Salehi's post At 6:55, how can nucleus , Posted 5 years ago. of the element by -4 and the atomic number. More advanced methods are needed to find roots of simultaneous systems of nonlinear equations. In alpha () decay or disintegration, a heavy (massive) nucleus emits a helium (42He) nucleus and another daughter nucleus. He didn't mention positron decay, which I am still very confused about. There are 5 different types of radioactive decay. Direct link to prajwalxdeval's post A beta particle is an ele, Posted 7 years ago. If we go back to the binding energy per mass number plot (\(B/A\) vs. \(A\)) we see that there is a bump (a peak) for \(A 60 100\). What is the interaction between the Th and alpha particle in the bound state? Alpha decay occurs in massive nuclei that have a large proton to neutron ratio. The mathematical relation in alpha decay is A Z X A - 4 Z - 2 Y + 4 2 He Alpha particles were given this name prior to discovering what kind of particles they represent. This means that the fossil is 11,460 years old. Ernest Rutherford distinguished alpha decay from other forms of radiation by studying the deflection of the radiation through a magnetic field. So he talks about the three types of radioactive decay, but how do you know what kind of decay say, Uranium, for instance, would give off? Also, note that because this was an alpha reaction, one . In order to understand this, we start by looking at the energetic of the decay, but we will need to study the quantum origin of the decay to arrive at a full explanation. Here, a high-energy radioactive nucleus can lower its energy state by emitting electromagnetic radiation. Now, using the same concept, solve the following problem. \(\log t_{1 / 2} \propto \frac{1}{\sqrt{Q_{\alpha}}}\), At short distance we have the nuclear force binding the, At long distances, the coulomb interaction predominates. In order to get some insight on the behavior of \(G\) we consider the approximation R Rc: \[G=\frac{1}{2} \sqrt{\frac{E_{G}}{Q_{\alpha}}} g\left(\sqrt{\frac{R}{R_{c}}}\right) \approx \frac{1}{2} \sqrt{\frac{E_{G}}{Q_{\alpha}}}\left[1-\frac{4}{\pi} \sqrt{\frac{R}{R_{c}}}\right] \nonumber\], \[\boxed{E_{G}=\left(\frac{2 \pi Z_{\alpha} Z e^{2}}{\hbar c}\right)^{2} \frac{\mu c^{2}}{2}} \nonumber\]. We can approximate the finite difference with the relevant gradient: \[\begin{align} So thorium-234 is our other product. But as this is an example there is no element with 10 as the atomic weight. Multiply the obtained result with the initial activity to know the final activity value. The relation between any parent and daughter element is that the rate of decay of a radioactive isotope is dependent on the amount of parent isotope that is remaining. The following tools can generate any one of the values from the other three in the half-life formula for a substance undergoing decay to decrease by half. A beta particle is an electron. To return to a stable state, these nuclei emit electromagnetic radiation in the form of one or multiple gamma rays. This method was used by NASA for its mission to Mars. So we lost a neutron, Alpha particles were given this name prior to discovering what kind of particles they represent. The steps to find the radioactive decay are given here. In -decay, the mass number of the product nucleus (daughter nucleus) is four less than that of the decaying nucleus (parent nucleus), while the atomic number decreases by two. This type of decay usually occurs in larger . Write a balanced nuclear equation for the alpha decay of thorium-232. Let's do beta decay. He holds bachelor's degrees in both physics and mathematics. in my two neutrons here. Q_{\alpha} &=[B(A-4, Z-2)-B(A, Z-2)]+[B(A, Z-2)-B(A, Z)]+B\left({ }^{4} H e\right) \\[4pt] &\approx -4 \frac{\partial B}{\partial A}-2 \frac{\partial B}{\partial Z}+B\left({ }^{4} H e\right) \\[4pt] &=28.3-4 a_{v}+\frac{8}{3} a_{s} A^{-1 / 3}+4 a_{c}\left(1-\frac{Z}{3 A}\right)\left(\frac{Z}{A^{1 / 3}}\right)-4 a_{s y m}\left(1-\frac{2 Z}{A}+3 a_{p} A^{-7 / 4}\right)^{2} \end{align}\], Since we are looking at heavy nuclei, we know that \(Z 0.41A\) (instead of \(Z A/2\)) and we obtain, \[Q_{\alpha} \approx-36.68+44.9 A^{-1 / 3}+1.02 A^{2 / 3}, \nonumber\]. Since all particles possess some rest energy in the form of mass, which we can find through the mass-energy equivalence method, we can then find the change in energy by comparing them. Direct link to Andrew M's post The nucleus has nuclear e, Posted 3 years ago. Other operations rely on theorems and algorithms from number theory, abstract algebra and other advanced fields to compute results. in our nuclear equation. In general, the alpha decay equation is represented as follows: Z A X Z 2 A 4 Y + 2 4 He where, Z A X is the parent nucleus The GeigerNuttall law or GeigerNuttall rule relates to the decay constant of a radioactive isotope with the energy of the alpha particles emitted. Learn about radioactive decay (alpha, beta, & gamma), how to balance nuclear equations for nuclear decay, and how to predict the products of nuclear reactions. So, for U-235 for example, when it decays via -decay, a Geiger counter will only detect it if there is no 'window' on the detector as alpha particles cannot penetrate through solid matter very far. stands for metastable, which means a nucleus Alpha decay is schematically shown in the figure below. For example, any of uranium isotopes such as (23892U) may emit an alpha particle and thus become a thorium isotope (23490Th). ejected from the nucleus. Get immediate feedback and guidance with step-by-step solutions and Wolfram Problem Generator. However, now we know that alpha particles are nothing more but helium nuclei. These results finally give an answer to the questions we had regarding alpha decay. An alpha particle, which is the same as a helium nucleus, is represented by 4 2H e. How would you complete the equation for this reaction? Sort by: Top Voted Questions Tips & Thanks Want to join the conversation? As per this rule, short-lived isotopes emit more energetic alpha particles than long-lived ones. Directions: Identify the following as alpha, beta, gamma, or neutron. As in chemistry, we expect the first reaction to be a spontaneous reaction, while the second one does not happen in nature without intervention. Finally the probability of tunneling is given by \(P_{T}=e^{-2 G} \), where G is calculated from the integral, \[G=\int_{R}^{R_{C}} d r \kappa(r)=\int_{R}^{R_{C}} d r \sqrt{\frac{2 \mu}{\hbar^{2}}\left(\frac{Z_{\alpha} Z^{\prime} e^{2}}{r}-Q_{\alpha}\right)} \nonumber\], We can solve the integral analytically, by letting \( r=R_{c} y=y \frac{Z_{\alpha} Z^{\prime} e^{2}}{Q_{\alpha}}\), then, \[G=\frac{Z_{\alpha} Z_{0} e^{2}}{\hbar c} \sqrt{\frac{2 \mu c^{2}}{Q_{\alpha}}} \int_{R / R_{C}}^{1} d y \sqrt{\frac{1}{y}-1} \nonumber\], \[G=\frac{Z_{\alpha} Z^{\prime} e^{2}}{\hbar c} \sqrt{\frac{2 \mu c^{2}}{Q_{\alpha}}}\left[\arccos \left(\sqrt{\frac{R}{R_{c}}}\right)-\sqrt{\frac{R}{R_{c}}} \sqrt{1-\frac{R}{R_{c}}}\right]=\frac{Z_{\alpha} Z^{\prime} e^{2}}{\hbar c} \sqrt{\frac{2 \mu c^{2}}{Q_{\alpha}}} \frac{\pi}{2} g\left(\sqrt{\frac{R}{R_{c}}}\right) \nonumber\], where to simplify the notation we used the function, \[g(x)=\frac{2}{\pi}\left(\arccos (x)-x \sqrt{1-x^{2}}\right) . For example, a Carbon-14 nucleus (Carbon-14 has 6 protons and 8 neutrons in the nucleus, that is 6 + 8 = 14 nucleons in total) turns into a Nitrogen-14 nucleus after a beta minus decay (Nitrogen-14 contain 7 protons and 7 neutrons in the nucleus). If we divide then the total barrier range into small slices, the final probability is the product of the probabilities \(d P_{T}^{k}\) of passing through all of the slices. When \(Q\) > 0 energy is released in the nuclear reaction, while for \(Q\) < 0 we need to provide energy to make the reaction happen. This decay leads to a decrease in the mass number and atomic number, due to the release of a helium atom. Vedantu LIVE Online Master Classes is an incredibly personalized tutoring platform for you, while you are staying at your home. and two neutrons) changes the mass number. The three important types of radioactive decay are Alpha decay, Beta decay and Gamma decay. Polonium nucleus has 84 protons and 126 neutrons, therefore the proton to neutron ratio is Z/N = 84/126, or 0.667. You can find websites that offer step-by-step explanations of various concepts, as well as online calculators and other tools to help you practice. A general equation for this type of alpha decay radiation is: AZXZ-4Z-2Y+42He Z A X Z - 2 Z - 4 Y + 2 4 He . When Thorium performs beta decay and becomes protactinium, would the product be an ion since a proton was added, and a beta particle was released out of the atom, not keeping the charges equaled? by -2. Coulomb repulsion grows in fact as \(Z^2\), much faster than the nuclear force which is proportional to \(A\). The total energy is given by \(E=Q_{\alpha} \) and is the sum of the potential (Coulomb) and kinetic energy. I've got a test coming up soon and I cannot fail. However, decay is just one type of radioactive decay. happening visually, we're starting off with a uranium nucleus which is unstable, it's going particle is two plus. Well, 234 minus 90, 234 minus 90 gives us the number of neutrons. ThoughtCo. How do we know which elements will undergo which kind of decay without actually observing them? 241 Am 95 Z X A + 4 He 2. The reason is because there are too many protons in the alpha decay of the nucleus, leading to excessive rejection. So we need 90 positive charges. Then the heavier nuclei will want to decay toward this lighter nuclides, by shedding some protons and neutrons. negative charge here, so I have a negative one charge, and so I must need 91 positive charges, because 91 positive charges and one negative charge gives me 90 positive charges on the right. The nuclear force is a short-range force that drops quickly in strength beyond 1 femtometer whereas the electromagnetic force has a very vast range. You would nee. In the \(\alpha\) decay we have specifically: \[\ce{_{Z}^{A} X_N -> _{Z-2}^{A-4} X_{N-2}^{\prime}} + \alpha \nonumber\]. ejected from this nucleus, so we're losing this alpha particle, and what's left behind How to calculate the products of an alpha decay. Click Start Quiz to begin! E.g, why can't U-238 do beta decay? What are the 5 types of radioactive decay? Moreover, the nuclear mass also decreases, bringing a decrease in the stored energy in the daughter nucleus (recall the mass-energy equivalence). All you have to do is enter the isotope name and initial activity, decay time and half-life details to get the final activity value. The electromagnetic force is a disruptive force that breaks the nucleus apart. Book: Introduction to Applied Nuclear Physics (Cappellaro), { "3.01:_Review_-_Energy_Eigenvalue_Problem" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "3.02:_Unbound_Problems_in_Quantum_Mechanics" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "3.03:_Alpha_Decay" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()" }, { "00:_Front_Matter" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "01:_Introduction_to_Nuclear_Physics" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "02:_Introduction_to_Quantum_Mechanics" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "03:_Radioactive_Decay_Part_I" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "04:_Energy_Levels" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "05:_Nuclear_Structure" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "06:_Time_Evolution_in_Quantum_Mechanics" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "07:_Radioactive_Decay_Part_II" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "08:_Applications_of_Nuclear_Science_(PDF_-_1.4MB)" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "zz:_Back_Matter" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()" }, [ "article:topic", "alpha decay", "license:ccbyncsa", "showtoc:no", "Gamow factor", "program:mitocw", "authorname:pcappellaro", "licenseversion:40", "source@https://ocw.mit.edu/courses/22-02-introduction-to-applied-nuclear-physics-spring-2012/" ], https://phys.libretexts.org/@app/auth/3/login?returnto=https%3A%2F%2Fphys.libretexts.org%2FBookshelves%2FNuclear_and_Particle_Physics%2FBook%253A_Introduction_to_Applied_Nuclear_Physics_(Cappellaro)%2F03%253A_Radioactive_Decay_Part_I%2F3.03%253A_Alpha_Decay, \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}}}\) \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash{#1}}} \)\(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\) \(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\)\(\newcommand{\AA}{\unicode[.8,0]{x212B}}\), 3.2: Unbound Problems in Quantum Mechanics, Quantum mechanics description of alpha decay, source@https://ocw.mit.edu/courses/22-02-introduction-to-applied-nuclear-physics-spring-2012/, status page at https://status.libretexts.org.

Moringa, Garlic And Ginger, Religious Easter Poems, Articles A